#6 Circles – Chords of a Circle – Problem Solving (with a Bonus trick to find square roots) | circles chords | Website providing Australia’s #1 song chords

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Circles – Part 6 – Here is another challenging question involving the theorems related with the Chords of a Circle.

The centre of the circle is O. The radius of the circle is 5cm. AB=AC=6cm. Find the length of BC.

Theorems Involved: A radius or diameter that is perpendicular to a chord divides the chord into two equal parts and vice versa. In the above circle, if the radius OB is perpendicular to the chord PQ then PA = AQ. Converse: The perpendicular bisector of a chord passes through the center of a circle.

All the three angles situated within the isosceles triangle are acute, which signifies that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°, which means we can find out the third angle of a triangle if the two angles of an isosceles triangle are known.

By using these theories on circles and isosceles triangles the entire solution to the question presented is explained in the video.

This video is mainly focus on the syllabus content of G.C.E Ordinary level students and primary and secondary class contents.

To solve this problem, we built two simultaneous equations and equate them since we continued the solution with two unknowns BM and x.

So finally, we have also showed you how to get the square root without using a calculator. Here we assumed calculators are not allowed during your exams.

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#6 Circles – Chords of a Circle – Problem Solving (with a Bonus trick to find square roots).

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